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36x^2-69x-36=0
a = 36; b = -69; c = -36;
Δ = b2-4ac
Δ = -692-4·36·(-36)
Δ = 9945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9945}=\sqrt{9*1105}=\sqrt{9}*\sqrt{1105}=3\sqrt{1105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-3\sqrt{1105}}{2*36}=\frac{69-3\sqrt{1105}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+3\sqrt{1105}}{2*36}=\frac{69+3\sqrt{1105}}{72} $
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